问题描述
python中有没有用于浮点数的range()函数例如
Is there any range() function in python for float numbers for example
a=0.6
if a in range(0,1):
a=3
我该如何实现?
推荐答案
如果我没看错，你想测试一个数字是否在另外两个数字之间，所以使用:
If I'm reading correctly, you want to test if a number is between two other numbers, so use:
a = 0.6
if 0 <= a < 1: # change to `<= 1` to be inclusive
a = 3
您不需要生成范围并进行成员资格测试 - 除非您有一组离散值，您的 a 应该匹配 - Python 中的内置 range3.x 可以对 int 进行有效的查找，因为它可以优化成员资格测试.如果你在一个很大的范围内有大量的离散值，那么你最好还是用数学方法来做.
You don't need to generate a range and do membership testing - unless you have a discrete set of values that your a should match - the builtin range in Python 3.x can do efficient lookups for ints as it can optimise membership testing. If you have a large amount of discrete values in a large range, then you'd be better of doing it mathematically anyway.
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