问题描述
我有一个名为 Object 的类，用于存储一些数据.
I have a class called Object which stores some data.
我想使用这样的函数通过引用返回它:
I would like to return it by reference using a function like this:
Object& return_Object();
然后，在我的代码中，我会这样称呼它:
Then, in my code, I would call it like this:
Object myObject = return_Object();
我已经编写了这样的代码并且它可以编译.但是，当我运行代码时，我始终遇到段错误.通过引用返回类对象的正确方法是什么?
I have written code like this and it compiles. However, when I run the code, I consistently get a seg fault. What is the proper way to return a class object by reference?
推荐答案
您可能正在返回堆栈上的对象.也就是说，return_Object() 可能看起来像这样:
You're probably returning an object that's on the stack. That is, return_Object() probably looks like this:
Object& return_Object()
{
Object object_to_return;
// ... do stuff ...
return object_to_return;
}
如果这是你正在做的事情，那你就不走运了 - object_to_return 已经超出范围并在 return_Object 的末尾被破坏，所以 myObject 指的是一个不存在的对象.您要么需要按值返回，要么返回在更广泛范围内声明的 Object 或 new 到堆上.
If this is what you're doing, you're out of luck - object_to_return has gone out of scope and been destructed at the end of return_Object, so myObject refers to a non-existent object. You either need to return by value, or return an Object declared in a wider scope or newed onto the heap.
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