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        从菜单中显示 MYSQL 数据

        Display MYSQL Data From a Menu(从菜单中显示 MYSQL 数据)
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                • 本文介绍了从菜单中显示 MYSQL 数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着跟版网的小编来一起学习吧!

                  问题描述

                  我有一个 MYSQL 数据库,其中包含许多字段,例如财产、卧室、大小等

                  I have a MYSQL database with a number of fields such as property, bedrooms, size etc

                  我有两个下拉列表,其中包含数据库中的数据

                  I have two dropdown list with data that is contained within the database

                  提交选项时,我希望打开一个显示结果的新页面.我收到错误消息 mysql_fetch_assoc(): 提供的参数不是有效的 MySQL 并且不知道如何解决这个问题!非常感谢帮助...我了解 SQL 注入,并希望在我让本节开始工作后纠正此问题

                  When submitting the options I want a new page to open displaying the results. I am getting the error message mysql_fetch_assoc(): supplied argument is not a valid MySQL and have no idea how to fix this! help much appreciated...I know about SQL injections and looking to rectify this after I get this section working first

                  HTML

                       <form method="get" action="submit.php">
                  
                       Number:  <select name="property">
                       <option value="Aviemore House">Aviemore House</option>
                       <option value="Dalfaber House">Dalfaber House</option>
                       </select>
                       <br>
                  
                       Name: <select name="bedrooms">
                       <option value="2">2</option>
                       <option value="3">3</option></select>
                       <br>
                  
                      <input type="submit" value="submit" />
                      </form>
                  

                  PHP

                   <?php
                  
                   require 'defaults.php';
                   require 'database.php';
                  
                  
                   $property = $_GET['property'] ;
                   $bedrooms = $_GET['bedrooms'] ;
                  
                   $query = "select FROM properties where property = '$property' & bedrooms = '$bedrooms'";
                  
                   while ($row = mysql_fetch_assoc($result))
                   {
                  $r[] = $row;
                   }
                  
                   ?>
                  

                  推荐答案

                  试试这个:

                  $query = "SELECT * FROM `properties` WHERE property = '{$property}' AND bedrooms = '{$bedrooms}'";
                  $row=mysql_query($query);
                  

                  您的 sql 格式错误,需要执行查询.

                  Your sql is malformatted and need to execute the query.

                  这篇关于从菜单中显示 MYSQL 数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持跟版网!

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