问题描述

使用以下代码显示我的 Twitter 个人资料中的朋友列表.我想一次只加载一个特定的数字，比如 20，然后在底部提供分页链接，第一个 1-2-3-4-5(无论多少除以限制)最后

Using the following code to display a list of friends from my twitter profile. Id like to only load a certain number at a time, say 20, then provide pagination links at the bottom for First 1-2-3-4-5(however many divided by limit) Last

$xml = simplexml_load_string($rawxml);

foreach ($xml->id as $key => $value) 
{
    $profile           = simplexml_load_file("https://twitter.com/users/$value");
    $friendscreenname  = $profile->{"screen_name"};
    $profile_image_url = $profile->{"profile_image_url"};

    echo "<a href=$profile_image_url>$friendscreenname</a><br>";
}

******更新******

******update******

if (!isset($_GET['i'])) {
    $i = 0;
} else {
    $i = (int) $_GET['i'];
}

$limit  = $i + 10;
$rawxml = OauthGetFriends($consumerkey, $consumersecret, $credarray[0], $credarray[1]);
$xml    = simplexml_load_string($rawxml);

foreach ($xml->id as $key => $value)
{

    if ($i >= $limit) {
        break;
    }

    $i++;
    $profile           = simplexml_load_file("https://twitter.com/users/$value");
    $friendscreenname  = $profile->{"screen_name"};
    $profile_image_url = $profile->{"profile_image_url"};

    echo "<a href=$profile_image_url>$friendscreenname</a><br>";
}

echo "<a href=step3.php?i=$i>Next 10</a><br>";

这行得通，只需要偏移从 $i 开始的输出.思考array_slice?

This works, just have to offset the output starting at $i. Thinking array_slice?

推荐答案

一个非常优雅的解决方案是使用 LimitIterator:

A very elegant solution is using a LimitIterator:

$xml = simplexml_load_string($rawxml);
// can be combined into one line
$ids = $xml->xpath('id'); // we have an array here
$idIterator = new ArrayIterator($ids);
$limitIterator = new LimitIterator($idIterator, $offset, $count);
foreach($limitIterator as $value) {
    // ...
}

// or more concise
$xml = simplexml_load_string($rawxml);
$ids = new LimitIterator(new ArrayIterator($xml->xpath('id')), $offset, $count);
foreach($ids as $value) {
    // ...
}

这篇关于如何使用 PHP 在 foreach 循环中对行进行分页的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！