问题描述

我有一个txt文件，其内容是:

I have txt file whose contents are:

u041fu0435u0440u0432u044bu0439_u0438u043du0442u0435u0440u0430u043au0442u0438u04u04u043u04u04u043u04u043u043u04u04304u0440u043du0435u0442_u043au0430u043du0430u043b

u041fu0435u0440u0432u044bu0439_u0438u043du0442u0435u0440u0430u043au0442u0438u0432u043du044bu0439_u0438u043du0442u0435u0440u043du0435u0442_u043au0430u043du0430u043b

我怎样才能读取这样的文件来得到这样的结果:

How can I read such file to get result like this:

Первый_интерактивный_интернет_канал"

"Первый_интерактивный_интернет_канал"

如果我输入:

string str = _T("u041fu0435u0440u0432u044bu0439_u0438u043du0442u0435u0440u0430u043au0442u0438u0432u043du044bu0439_u0438u043du0442u0435u0440u043du0435u0442_u043au0430u043du0430u043b");

然后结果 str 很好，但是如果我从文件中读取它，那么它与文件中的结果相同.我想这是因为 'u' 变成了 'u'.有没有简单的方法将 uxxxx 符号转换为 C++ 中的相应符号?

then result in str is good but if I read it from file then it is the same like in file. I guess it is because 'u' becomes 'u'. Is there simple way to convert uxxxx notation to corresponding symbols in C++?

推荐答案

以下是 MSalters 建议的示例:

Here is an example for MSalters's suggestion:

#include <iostream>
#include <string>
#include <fstream>
#include <algorithm>
#include <sstream>
#include <iomanip>
#include <locale>

#include <boost/scoped_array.hpp>
#include <boost/regex.hpp>
#include <boost/numeric/conversion/cast.hpp>

std::wstring convert_unicode_escape_sequences(const std::string& source) {
  const boost::regex regex("\\u([0-9A-Fa-f]{4})");  // NB: no support for non-BMP characters
  boost::scoped_array<wchar_t> buffer(new wchar_t[source.size()]);
  wchar_t* const output_begin = buffer.get();
  wchar_t* output_iter = output_begin;
  std::string::const_iterator last_match = source.begin();
  for (boost::sregex_iterator input_iter(source.begin(), source.end(), regex), input_end; input_iter != input_end; ++input_iter) {
    const boost::smatch& match = *input_iter;
    output_iter = std::copy(match.prefix().first, match.prefix().second, output_iter);
    std::stringstream stream;
    stream << std::hex << match[1].str() << std::ends;
    unsigned int value;
    stream >> value;
    *output_iter++ = boost::numeric_cast<wchar_t>(value);
    last_match = match[0].second;
  }
  output_iter = std::copy(last_match, source.end(), output_iter);
  return std::wstring(output_begin, output_iter);
}

int wmain() {
  std::locale::global(std::locale(""));
  const std::wstring filename = L"test.txt";
  std::ifstream stream(filename.c_str(), std::ios::in | std::ios::binary);
  stream.seekg(0, std::ios::end);
  const std::ifstream::streampos size = stream.tellg();
  stream.seekg(0);
  boost::scoped_array<char> buffer(new char[size]);
  stream.read(buffer.get(), size);
  const std::string source(buffer.get(), size);
  const std::wstring result = convert_unicode_escape_sequences(source);
  std::wcout << result << std::endl;
}

我总是惊讶于 C++ 中看似简单的事情是多么复杂.

I'm always surprised how complicated seemingly simple things like this are in C++.

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